Step 1: Identify the support reactions.
The beam is simply supported at points A and B, and a concentrated load of 50 kN acts at point C.
Step 2: Calculate reactions using equilibrium equations.
Taking moments and vertical force equilibrium, the reaction at support A is found to be 37.5 kN, while the reaction at B is 12.5 kN.
Step 3: Determine shear force at point C.
Shear force at point C just to the left of the applied load is equal to the reaction at A.
\[
V_C = 37.5 \text{ kN}
\]
Step 4: Conclusion.
Therefore, the shear developed at point C is 37.5 kN.