Step 1: Understanding the genetic inheritance of colour blindness.
Colour blindness is an X-linked recessive trait. In a colour-blind woman, the genotype is X\(^c\)X\(^c\), where X\(^c\) represents the X chromosome carrying the colour-blind allele. The man, being normal, will have the genotype X\(^N\)Y, where X\(^N\) represents the normal X chromosome and Y is the male sex chromosome.
Step 2: Genetic inheritance for a son.
Sons inherit their X chromosome from their mother and their Y chromosome from their father. Since the mother is colour-blind (X\(^c\)X\(^c\)), she can only pass on the X\(^c\) chromosome. The father, being normal, will pass on the Y chromosome. Thus, the son will inherit X\(^c\)Y, making him colour-blind.
Step 3: Conclusion.
Since the son will always inherit the X\(^c\) chromosome from his colour-blind mother, he will be colour-blind. Therefore, the chance that their boy child will be colour-blind is 100%. The correct answer is 100.