Question:
If \(a^2+b^2=41\) and \(ab=20\), then the value of \(a+b\) is
If \(a^2+b^2=41\) and \(ab=20\), then the value of \(a+b\) is
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Expand (a+b)^2 = a^2 + b^2 + 2ab and substitute the given values.
Updated On: Jul 8, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Use the identity.
\((a+b)^2=a^2+b^2+2ab\).
Step 2: Substitute.
\((a+b)^2=41+2(20)=41+40=81\).
Step 3: Take the positive root.
\(a+b=\sqrt{81}=9\).
\[\boxed{9}\]
\((a+b)^2=a^2+b^2+2ab\).
Step 2: Substitute.
\((a+b)^2=41+2(20)=41+40=81\).
Step 3: Take the positive root.
\(a+b=\sqrt{81}=9\).
\[\boxed{9}\]
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