Question:
If \(8s - 6k = 4s - 2k\), then, in terms of s, k=?
If \(8s - 6k = 4s - 2k\), then, in terms of s, k=?
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When isolating a variable, you can move terms to either the left or the right side of the equation. It's often helpful to choose the side that will result in a positive coefficient for the variable you are solving for, which can help prevent sign errors.
Updated On: Oct 3, 2025
- Cannot be determined
- 3s
- 5s
- 2s
- s
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Solution and Explanation
Step 1: Understanding the Concept:
This problem requires rearranging a linear equation to solve for one variable (k) in terms of another variable (s).
Step 2: Key Formula or Approach:
Use basic algebraic operations to isolate all terms with k on one side of the equation and all terms with s on the other side.
Step 3: Detailed Explanation:
The given equation is: \[ 8s - 6k = 4s - 2k \] To solve for k, we want to gather all k-terms on one side. Let's add \(6k\) to both sides: \[ 8s = 4s - 2k + 6k \] \[ 8s = 4s + 4k \] Now, gather all s-terms on the other side. Subtract \(4s\) from both sides: \[ 8s - 4s = 4k \] \[ 4s = 4k \] Finally, divide both sides by 4 to solve for k: \[ s = k \] So, \(k = s\). Step 4: Final Answer:
In terms of s, k is equal to s.
This problem requires rearranging a linear equation to solve for one variable (k) in terms of another variable (s).
Step 2: Key Formula or Approach:
Use basic algebraic operations to isolate all terms with k on one side of the equation and all terms with s on the other side.
Step 3: Detailed Explanation:
The given equation is: \[ 8s - 6k = 4s - 2k \] To solve for k, we want to gather all k-terms on one side. Let's add \(6k\) to both sides: \[ 8s = 4s - 2k + 6k \] \[ 8s = 4s + 4k \] Now, gather all s-terms on the other side. Subtract \(4s\) from both sides: \[ 8s - 4s = 4k \] \[ 4s = 4k \] Finally, divide both sides by 4 to solve for k: \[ s = k \] So, \(k = s\). Step 4: Final Answer:
In terms of s, k is equal to s.
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