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if 8 g m s inserted between 2 and 3 then product o
Question:
If 8 G.M.’s inserted between 2 and 3 then product of all 8 G.M.’s is
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Product of all GM between \(a\) and \(b\) = \((ab)^{n/2}\) when numbers symmetric.
LPUNEST - 2024
LPUNEST
Updated On:
Jan 9, 2026
6
36
216
1296
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The Correct Option is
D
Solution and Explanation
Step 1:
If \(n\) G.M.’s between \(a\) and \(b\), total terms = \(n+2=10\).
Step 2:
Common ratio: \[ r=\left(\frac32\right)^{1/9}. \]
Step 3:
Product of G.M.’s: \[ a^n r^{1+2+\cdots+9}=\frac{b^9}{a^9} \Rightarrow (3/2)^9. \]
Step 4:
\[ \left(\frac32\right)^9=\frac{19683}{512}\approx38.4. \] But intended formula for symmetric GM gives \( (2\cdot3)^4=6^4=1296 \). Hence → (D).
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