We are given the system of equations:
\[
3x + 4y = 10 \quad \text{(1)},
\]
\[
2x - 2y = 2 \quad \text{(2)}.
\]
First, solve equation (2) for \( x \):
\[
2x = 2 + 2y \quad \Rightarrow \quad x = 1 + y.
\]
Substitute this into equation (1):
\[
3(1 + y) + 4y = 10 \quad \Rightarrow \quad 3 + 3y + 4y = 10 \quad \Rightarrow \quad 7y = 7 \quad \Rightarrow \quad y = 1.
\]
Substitute \( y = 1 \) into \( x = 1 + y \):
\[
x = 1 + 1 = 2.
\]
Thus, \( x = 2 \) and \( y = 1 \), so the solution is \( \boxed{x = 2, y = 1} \).