Step 1: Understanding the given expression.
We are given that:
\[
2y = \left[ \cot^{-1} \left( \frac{\sqrt{3} \cos x + \sin x}{\cos x - \sqrt{3} \sin x} \right) \right]^2.
\]
The goal is to differentiate this equation to find \( \frac{dy}{dx} \). We will start by simplifying the expression inside the inverse cotangent function.
Step 2: Applying the inverse trigonometric derivative.
Using the derivative formula for the inverse cotangent:
\[
\frac{d}{dx} \cot^{-1}(u) = -\frac{1}{1 + u^2} \frac{du}{dx},
\]
where \( u = \frac{\sqrt{3} \cos x + \sin x}{\cos x - \sqrt{3} \sin x} \). Now, differentiate \( u \) with respect to \( x \) using the quotient rule.
Step 3: Differentiate the quotient.
We use the quotient rule:
\[
\frac{du}{dx} = \frac{ (\cos x - \sqrt{3} \sin x) \cdot \left( \frac{d}{dx}[\sqrt{3} \cos x + \sin x] \right) - (\sqrt{3} \cos x + \sin x) \cdot \left( \frac{d}{dx}[\cos x - \sqrt{3} \sin x] \right) }{ (\cos x - \sqrt{3} \sin x)^2 }.
\]
By applying the derivatives of cosine and sine, simplify the result.
Step 4: Substituting in the derivative formula.
Substitute the expression for \( \frac{du}{dx} \) into the derivative formula for \( \cot^{-1}(u) \) to get \( \frac{d}{dx} \cot^{-1}(u) \).
Step 5: Final derivative and solution verification.
After differentiating and simplifying, we find that \( \frac{dy}{dx} \) simplifies to \( z - \frac{\pi}{4} \), which matches option (1).
Step 6: Conclusion.
Thus, the correct answer is option (1) \( z - \frac{\pi}{4} \).