Question:
If 24th February, 2010 was Wednesday, what day of the week will be 11th October in that year?
If 24th February, 2010 was Wednesday, what day of the week will be 11th October in that year?
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Break date differences month-wise, then apply modulo 7 to find the final day.
Updated On: Apr 21, 2026
- Friday
- Saturday
- Sunday
- Monday
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The Correct Option is D
Solution and Explanation
Concept:
Find the number of days between the two dates and use modulo 7.
Step 1: Count days from Feb 24 to Oct 11 (2010 is not a leap year).
Remaining days in Feb: \[ 28 - 24 = 4 \] Add months: \[ {March} = 31,\ {April} = 30,\ {May} = 31,\ {June} = 30 \] \[ {July} = 31,\ {August} = 31,\ {September} = 30,\ {October (till 11)} = 11 \] Total days: \[ 4 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 11 = 229 \]
Step 2: Find remainder.
\[ 229 \bmod 7 = 5 \]
Step 3: Add 5 days to Wednesday.
\[ {Wednesday} \rightarrow {Thursday (1)} \rightarrow {Friday (2)} \rightarrow {Saturday (3)} \rightarrow {Sunday (4)} \rightarrow {Monday (5)} \]
Hence, the day is Monday.
Step 1: Count days from Feb 24 to Oct 11 (2010 is not a leap year).
Remaining days in Feb: \[ 28 - 24 = 4 \] Add months: \[ {March} = 31,\ {April} = 30,\ {May} = 31,\ {June} = 30 \] \[ {July} = 31,\ {August} = 31,\ {September} = 30,\ {October (till 11)} = 11 \] Total days: \[ 4 + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 11 = 229 \]
Step 2: Find remainder.
\[ 229 \bmod 7 = 5 \]
Step 3: Add 5 days to Wednesday.
\[ {Wednesday} \rightarrow {Thursday (1)} \rightarrow {Friday (2)} \rightarrow {Saturday (3)} \rightarrow {Sunday (4)} \rightarrow {Monday (5)} \]
Hence, the day is Monday.
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