If \( 2 \log 5 + \frac{1}{2} \log 9 - \log 3 = \log x \), then the value of \( x \) is:
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For logarithmic equations, use the properties of logarithms to combine terms. Remember, \( \log a + \log b = \log(ab) \) and \( \log a - \log b = \log\left(\frac{a}{b}\right) \).
We are given:
\[
2 \log 5 + \frac{1}{2} \log 9 - \log 3 = \log x
\]
Step 1: Simplify the logarithmic terms.
The first term can be simplified as:
\[
2 \log 5 = \log 5^2 = \log 25
\]
The second term simplifies as:
\[
\frac{1}{2} \log 9 = \log 9^{1/2} = \log 3
\]
The third term is already \( \log 3 \).
Thus, the equation becomes:
\[
\log 25 + \log 3 - \log 3 = \log x
\]
Step 2: Simplify further.
Since \( \log 3 - \log 3 = 0 \), we have:
\[
\log 25 = \log x
\]
Step 3: Equate the terms.
Since \( \log 25 = \log x \), it follows that:
\[
x = 25
\]