20
The sequence given is a series of products of consecutive odd numbers taken three at a time. The general term for the sequence can be expressed as \( (2k-1)(2k+1)(2k+3) \), where \( k \) is the term number starting from 1. To find \( f(2) \), consider the sum of the first two terms of the series: \[ 1\cdot3\cdot5 + 3\cdot5\cdot7 = 15 + 105 = 120 \] Given that this sum is expressed by the formula \( n(n+1)f(n) \) for \( n = 2 \), we have: \[ 2(2+1)f(2) = 120 \quad \Rightarrow \quad 6f(2) = 120 \quad \Rightarrow \quad f(2) = 20 \] Thus, \( f(2) = 20 \), which confirms the correct answer as option (4).
If the real-valued function
\[ f(x) = \sin^{-1}(x^2 - 1) - 3\log_3(3^x - 2) \]is not defined for all \( x \in (-\infty, a] \cup (b, \infty) \), then what is \( 3^a + b^2 \)?
Given the function:
\[ f(x) = \frac{2x - 3}{3x - 2} \]
and if \( f_n(x) = (f \circ f \circ \ldots \circ f)(x) \) is applied \( n \) times, find \( f_{32}(x) \).