Given, \(\frac{1}{6!}+\frac{1}{7!}=\frac{x}{8!}\)
\(⇒\frac{1}{6!}+\frac{1}{7\times6!}=\frac{x}{8\times7\times6!}\)
\(⇒\frac{1}{6!}(1+\frac{1}{7})=\frac{x}{8\times7\times6!}\)
\(⇒1+\frac{1}{7}=\frac{x}{8\times7}\)
\(⇒\frac{8}{7}=\frac{x}{8\times7}\)
\(⇒x=\frac{8\times8\times7}{7}\)
\(∴x=64\)
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.
Permutation is the method or the act of arranging members of a set into an order or a sequence.
Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.