Question:
Identify X and Y formed in the following two reactions.
\[
(i) \, \text{Decan-1-ol} \xrightarrow{\text{Jones reagent}} X
\]
\[
(ii) \, \text{Sodium salt of X} \xrightarrow{\text{NaOH/CaO,} \Delta} Y
\]
Identify X and Y formed in the following two reactions.
\[ (i) \, \text{Decan-1-ol} \xrightarrow{\text{Jones reagent}} X \]
\[ (ii) \, \text{Sodium salt of X} \xrightarrow{\text{NaOH/CaO,} \Delta} Y \]
\[ (i) \, \text{Decan-1-ol} \xrightarrow{\text{Jones reagent}} X \]
\[ (ii) \, \text{Sodium salt of X} \xrightarrow{\text{NaOH/CaO,} \Delta} Y \]
Show Hint
Jones reagent oxidizes primary alcohols to carboxylic acids, and soda lime decarboxylates carboxylic acids to form hydrocarbons.
Updated On: May 5, 2026
- X = Decanoic acid, Y = Nonane
- X = Octanoic acid, Y = Heptane
- X = 1-Methoxy nonane, Y = Octane
- X = Decan-2-one, Y = Octane
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The Correct Option is A
Solution and Explanation
Step 1: Understand the reaction of Decan-1-ol with Jones reagent.
The Jones reagent is a strong oxidizing agent that will oxidize primary alcohols to carboxylic acids. In this case, decan-1-ol (\( C_{10}H_{21}OH \)) will be oxidized to decanoic acid (\( C_{10}H_{19}COOH \)).
Step 2: Reaction of sodium salt of X with NaOH/CaO.
The second reaction involves the sodium salt of decanoic acid being heated with soda lime (a mixture of sodium hydroxide and calcium oxide). This reaction is known as decarboxylation, which removes the carboxyl group (\( -COOH \)) and results in the formation of a hydrocarbon. The product in this case will be nonane (\( C_9H_{20} \)).
Step 3: Conclusion.
Thus, the correct compounds are:
- X = Decanoic acid
- Y = Nonane
The correct answer is option (A).
The Jones reagent is a strong oxidizing agent that will oxidize primary alcohols to carboxylic acids. In this case, decan-1-ol (\( C_{10}H_{21}OH \)) will be oxidized to decanoic acid (\( C_{10}H_{19}COOH \)).
Step 2: Reaction of sodium salt of X with NaOH/CaO.
The second reaction involves the sodium salt of decanoic acid being heated with soda lime (a mixture of sodium hydroxide and calcium oxide). This reaction is known as decarboxylation, which removes the carboxyl group (\( -COOH \)) and results in the formation of a hydrocarbon. The product in this case will be nonane (\( C_9H_{20} \)).
Step 3: Conclusion.
Thus, the correct compounds are:
- X = Decanoic acid
- Y = Nonane
The correct answer is option (A).
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