Question

Identify the type of reaction:

• A. Electrophilic addition
• B. Free radical substitution
• C. Nucleophilic addition
• D. Free radical addition

Hint:

Addition of HX (like HBr) to alkenes generally follows electrophilic addition mechanism and Markovnikov’s rule.

Answer 1

The Correct Option is A

Step 1: Identify the reactant.
The reactant is an alkene \( (CH_3-CH=CH_2) \) which contains a \( \pi \)-bond.

Step 2: Nature of alkene reaction.
Alkenes are electron-rich due to the \( \pi \)-bond, so they attract electrophiles.

Step 3: Identify reagent.
\( HBr \) provides \( H^+ \) (electrophile) and \( Br^- \).

Step 4: Mechanism.
First step: \( H^+ \) attacks the double bond forming a carbocation.
Second step: \( Br^- \) attacks the carbocation.

Step 5: Product formed.
Product is \( CH_3-CH(Br)-CH_3 \), following Markovnikov’s rule.

Step 6: Type of reaction.
Since electrophile adds across double bond, it is electrophilic addition.

Step 7: Final conclusion.
\[ \boxed{\text{Electrophilic addition}} \]