Question:

Identify the reaction in which hydrogen gas is not liberated

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- Aluminium reacts with both HCl and NaOH to liberate \( H_2 \) gas.
- \( NaBH_4 \) reacts with iodine to release hydrogen gas.
- \( BF_3 \) reacts with \( LiAlH_4 \) but does NOT liberate hydrogen gas.
Updated On: May 5, 2026
  • \( Al(s) + HCl(aq) \rightarrow \)
  • \( NaBH_4 + I_2 \rightarrow \)
  • \( BF_3 + LiAlH_4 \rightarrow \)
  • \( Al(s) + NaOH(aq) \rightarrow \)
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Use concept of hydride donors and metal reactivity

Hydrogen gas is generally produced when:

  • Active metals react with acids or bases
  • Hydride ions combine to release H_2

Step 2: Analyze reactions

(1) Al + HCl → Metal + acid ⇒ releases H_2

(2) NaBH_4 + I_2 → Hydride reacts ⇒ releases H_2

(3) BF_3 + LiAlH_4 → Formation of complex hydride, no free H_2 gas

(4) Al + NaOH → Metal + base ⇒ releases H_2

Final Answer: \mathbf{(3)}

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