Identify the process in which change in the oxidation state is five :
Show Hint
- \(\mathrm{Cr_2O_7^{2-} \to 2Cr^{3+}}\)
- \(\mathrm{MnO_4^{-} \to Mn^{2+}}\)
- \(\mathrm{CrO_4^{2-} \to Cr^{3+}}\)
- \(\mathrm{C_2O_4^{2-} \to 2CO_2}\)
The Correct Option is B
Solution and Explanation
Option (2): Mn in \(\mathrm{MnO_4^{-}}\): \(x - 8 = -1 \Rightarrow x = +7\); in \(\mathrm{Mn^{2+}}\) it is +2. Change = 5.
Option (3): Cr in \(\mathrm{CrO_4^{2-}}\): \(x - 8 = -2 \Rightarrow x = +6\); to +3. Change = 3.
Option (4): C in \(\mathrm{C_2O_4^{2-}}\): \(2x - 8 = -2 \Rightarrow x = +3\); in \(\mathrm{CO_2}\) it is +4. Change = 1.
Only option (2) has a change of five.
Answer: (2) \(\mathrm{MnO_4^{-} \to Mn^{2+}}\)
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