Question:

Identify the pair in which the geometry of the species is \(T\)-shape and square-pyramidal, respectively :

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Use VSEPR: T-shape needs 3 bond pairs + 2 lone pairs (sp3d); square pyramid needs 5 bond pairs + 1 lone pair (sp3d2).
Updated On: Nov 11, 2026
  • \(\mathrm{ClF_3}\) and \(\mathrm{IO_4^-}\)
  • \(\mathrm{ICl_2^-}\) and \(\mathrm{ICl_5}\)
  • \(\mathrm{XeOF_2}\) and \(\mathrm{XeOF_4}\)
  • \(\mathrm{IO_3^-}\) and \(\mathrm{IO_2F_2^-}\)
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The Correct Option is C

Solution and Explanation

Option (1): \(\mathrm{ClF_3}\) is T-shaped (sp3d, 2 lone pairs) but \(\mathrm{IO_4^-}\) is tetrahedral. Not correct.
Option (2): \(\mathrm{ICl_2^-}\) is linear (3 lone pairs); \(\mathrm{ICl_5}\) is square pyramidal. Not correct.
Option (3): \(\mathrm{XeOF_2}\): Xe has 8 valence electrons; 2 are used in the Xe=O bond and 2 in the Xe-F bonds, leaving 4 electrons = 2 lone pairs. Three bonded atoms + 2 lone pairs (sp3d) gives a T-shape. \(\mathrm{XeOF_4}\): 5 bonded atoms + 1 lone pair (sp3d2) gives a square pyramid. Correct.
Option (4): \(\mathrm{IO_3^-}\) is pyramidal and \(\mathrm{IO_2F_2^-}\) is see-saw. Not correct.
Answer: (3) \(\mathrm{XeOF_2}\) and \(\mathrm{XeOF_4}\)
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