Question:
Identify the option in which elements are correctly arranged in the increasing order of their electronegativity values.
Identify the option in which elements are correctly arranged in the increasing order of their electronegativity values.
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Memorize the electronegativity order among common non-metals:
\[
\mathrm{P<S<Cl<O<F}
\]
Fluorine is the most electronegative element in the periodic table.
Updated On: Jun 12, 2026
- \(\mathrm{P < S < Cl < O < F}\)
- \(\mathrm{S < P < O < Cl < F}\)
- \(\mathrm{S < Cl < F < O < P}\)
- \(\mathrm{P < S < O < Cl < F}\)
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The Correct Option is A
Solution and Explanation
Concept:
Electronegativity is the tendency of an atom to attract the shared pair of electrons towards itself in a chemical bond.
General periodic trends are:
• Electronegativity increases from left to right across a period.
• Electronegativity decreases from top to bottom in a group.
• Fluorine possesses the highest electronegativity value among all elements. The approximate Pauling electronegativity values of the given elements are: \[ \mathrm{P}=2.19 \] \[ \mathrm{S}=2.58 \] \[ \mathrm{Cl}=3.16 \] \[ \mathrm{O}=3.44 \] \[ \mathrm{F}=3.98 \]
Step 1: Arrange the elements according to increasing electronegativity. Using the standard values, \[ 2.19<2.58<3.16<3.44<3.98 \] Therefore, \[ \mathrm{P<S<Cl<O<F} \]
Step 2: Compare with the given options. Only Option (A) matches the correct increasing order. Hence, \[ \boxed{\mathrm{P<S<Cl<O<F}} \]
• Electronegativity increases from left to right across a period.
• Electronegativity decreases from top to bottom in a group.
• Fluorine possesses the highest electronegativity value among all elements. The approximate Pauling electronegativity values of the given elements are: \[ \mathrm{P}=2.19 \] \[ \mathrm{S}=2.58 \] \[ \mathrm{Cl}=3.16 \] \[ \mathrm{O}=3.44 \] \[ \mathrm{F}=3.98 \]
Step 1: Arrange the elements according to increasing electronegativity. Using the standard values, \[ 2.19<2.58<3.16<3.44<3.98 \] Therefore, \[ \mathrm{P<S<Cl<O<F} \]
Step 2: Compare with the given options. Only Option (A) matches the correct increasing order. Hence, \[ \boxed{\mathrm{P<S<Cl<O<F}} \]
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