
The reaction depicted in the image is called the Gatterman-Koch reaction. This reaction involves the formylation of aromatic compounds like benzene to form benzaldehyde.
Explanation:
The setup typically involves bubbling CO and HCl through a solution of an aromatic ring and the catalyst. When benzene is used, the Gatterman-Koch reaction results in the formation of benzaldehyde:
Reaction: C6H6 + CO + HCl → C6H5CHO
This method is particularly useful because it directly converts benzene into benzaldehyde in one step.
This is distinct from other reactions listed in the options:
Thus, the correct answer is Gatterman-Koch reaction.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: H2Te is more acidic than H2S.
Reason R: Bond dissociation enthalpy of H2Te is lower than H2S.
In light of the above statements, choose the most appropriate from the options given below:


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)