Question:
Identify the correct statements from the following:
Oxidation of NaBH_4 with \(I_2\) gives \(B_2H_6\)
(ii) \(B_2H_6\) burns in oxygen and releases an enormous amount of energy
(iii) \(B_2H_6\) on hydrolysis gives a tribasic acid
Identify the correct statements from the following:
Oxidation of NaBH_4 with \(I_2\) gives \(B_2H_6\)
(ii) \(B_2H_6\) burns in oxygen and releases an enormous amount of energy
(iii) \(B_2H_6\) on hydrolysis gives a tribasic acid
Show Hint
Remember, when B₂H₆ undergoes hydrolysis, it forms boric acid, a tribasic acid.
Updated On: Mar 19, 2025
i, ii, iii
- i, ii, iii
- i, iii only
- ii, iii only
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
- (i) Oxidation of NaBH₄ with I₂ indeed gives \(B_2H_6\). This is a correct statement.
- (ii) \(B_2H_6\) does burn in oxygen, but the released energy is not enormous. Therefore, this statement is incorrect.
- (iii) \(B_2H_6\) on hydrolysis gives a tribasic acid, which is correct. Thus, the correct statements are: i and iii only.
- (ii) \(B_2H_6\) does burn in oxygen, but the released energy is not enormous. Therefore, this statement is incorrect.
- (iii) \(B_2H_6\) on hydrolysis gives a tribasic acid, which is correct. Thus, the correct statements are: i and iii only.
Was this answer helpful?
0
0
Top AP EAMCET Chemistry Questions
- If the $pK_a$ of acetic acid and $pK_b$ of dimethylamine are $4.76$ and $3.26$ respectively, the pH of dimethyl ammonium acetate solution is
- In the first order thermal decomposition of $C _{2} H _{5} I (g) \longrightarrow C _{2} H _{4}(g)+ HI (g)$, the reactant in the beginning exerts a pressure of $2$ bar in a closed vessel at $600 \,K$. If the partial pressure of the reactant is $0.1$ bar after $1000$ minutes at the same temperature the rate constant in $\min ^{-1}$ is $(\log 2=0.3010)$
- Isopropyl benzene on aerial oxidation followed by acid hydrolysis of the resulting compound yields
- Sodium nitrite is reacted with $H_2SO_4$ to form $NaHSO_4, HNO_3$, water and $X$. Gold is dissolved in aqua-regia to form water, $AuCl^{-}_4$ and $Y. X$ and $Y$ are respectively
- The average translational kinetic energy of a molecule in a gas becomes equal to $0.69\, eV$ at a temperature about [Boltzmann constant = $1.38 \times 10^{-23} \; J \; K^{-1}$]
View More Questions
Top AP EAMCET Chemical Reactions Questions
- Identify the halogen exchange reaction from the following
- Identify $Z$ in the following sequence of reactions. $\ce{ C_2 H_4 Br_2 ->[(i) Alc.KOH][(ii) NaNH_2] X ->[Red\, hot][Fe \,tube\, 873 K] Y ->[(CH_3CO)_2 O/\Delta][Anhyd. AlCl_3] Z}$
- An organic compound $X\left( C _{7} H _{7} Cl \right)$ when reacted with $KCN / C _{2} H _{5} OH$ gave major product $Y . Z$ is formed when $Y$ is reduced with $LiAlH _{4}$. What are $Y$ and $Z$ ?
- Acetic acid on heating with $ {NH_3}$ forms $A$. When $A$ reacts with $ {LiAlH_4}$ followed by hydrolysis gives $B$. When $B$ is heated with chloroform in $KOH$ medium gives $C$. What are $B$ and $C$ respectively?
Find the products formed if chlorine reacts with the cold and dilute sodium hydroxide solution.
View More Questions
Top AP EAMCET Questions
- If $\int \cos x . \cos 2x . \cos 5x dx = A \; \sin 2x + B \sin 4x + C \sin 6x + D \sin 8x + k $ (where $k$ is the arbitrary constant of integration), then $\frac{1}{B} + \frac{1}{C} = $
- If $k$ is one of the roots of the equation $x^2 - 25x + 24 = 0 $ such that $A = \begin{bmatrix}1&2&1\\ 3&2&3\\ 1&1&k\end{bmatrix} $ is a non-singular matrix, then $A^{-1}$ =
- If only $\frac{1}{51}^{th}$ ot the main current is to be passed through a galvanometer then the shunt required is $R_1$ and if only $\frac{1}{11}^{th}$ of the main voltage is to be developed across the galvanometer, then the resistance required is $R_2$. Then $\frac{R_2}{R_1} =$
- If $p$ and $q$ are respectively the global maximum and global minimum of the function $f(x) = x^2 e^{2x}$ on the interval $[-2, 2]$ , then $pe^{-4} + qe^4 = $
- If $\displaystyle\sum^n_{k - 1} \tan^{-1} \left( \frac{1}{k^2 + k + 1} \right) = \tan^{-1} (\theta) $ , then $\theta$ =
View More Questions