Question:
Identify the correct statements from the following:
I. Conjugate base of chloric acid is \( ClO^- \)
II. \( AlCl_3 \) is a Lewis acid
III. Conjugate base of \( NH_3 \) is \( NH_2^- \)
Identify the correct statements from the following:
I. Conjugate base of chloric acid is \( ClO^- \)
II. \( AlCl_3 \) is a Lewis acid
III. Conjugate base of \( NH_3 \) is \( NH_2^- \)
II. \( AlCl_3 \) is a Lewis acid
III. Conjugate base of \( NH_3 \) is \( NH_2^- \)
Show Hint
- A conjugate base is formed by removing \( H^+ \) from an acid.
- A Lewis acid is an electron pair acceptor (e.g., \( AlCl_3 \) with an incomplete octet).
Updated On: May 5, 2026
- I, II, III
- I, II only
- II, III only
- I, III only
Show Solution
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The Correct Option is C
Solution and Explanation
Let's analyze each statement to identify which ones are correct:
- Statement I: The conjugate base of chloric acid is \( ClO^- \).
- Chloric acid is actually \( HClO_3 \). When it loses a proton (\( H^+ \)), the conjugate base formed is \( ClO_3^- \), not \( ClO^- \).
- Therefore, Statement I is incorrect.
- Statement II: \( AlCl_3 \) is a Lewis acid.
- A Lewis acid is a species that can accept an electron pair. \( AlCl_3 \) has an incomplete octet and can accept electron pairs from donor molecules (Lewis bases), thereby acting as a Lewis acid.
- Therefore, Statement II is correct.
- Statement III: The conjugate base of \( NH_3 \) is \( NH_2^- \).
- Ammonia, \( NH_3 \), can lose a proton (\( H^+ \)) to form its conjugate base, \( NH_2^- \).
- Therefore, Statement III is correct.
Based on the above analysis, Statements II and III are correct. Thus, the correct answer is:
II, III only
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