Step 1: Count valence electrons of central atom.
In \(ClF_3\), chlorine is the central atom.
Chlorine has:
\[
7
\]
valence electrons.
Step 2: Count bond pairs.
Chlorine forms three bonds with three fluorine atoms.
So number of bond pairs is:
\[
3
\]
Step 3: Count lone pairs on chlorine.
Out of \(7\) valence electrons of chlorine, \(3\) electrons are used for bonding.
Remaining electrons:
\[
7-3=4
\]
These \(4\) electrons form:
\[
2
\]
lone pairs.
Step 4: Determine electron pair geometry.
Total electron pairs around chlorine:
\[
3+2=5
\]
Five electron pairs give trigonal bipyramidal electron pair arrangement.
Step 5: Determine molecular shape.
In \(ClF_3\), two lone pairs occupy equatorial positions to reduce repulsion.
The remaining three bond pairs form a T-shaped structure.
Therefore:
\[
ClF_3
\]
has:
\[
\text{T-shaped geometry with two lone pairs on chlorine}.
\]