Question

Identify the CORRECT set of details from the following: 
A. \([\text{Co}(\text{NH}_3)_6]^{3+}\): Inner orbital complex; \(d^2sp^3\) hybridized 
B. $[\text{MnCl}_6]^{3-}$: Outer orbital complex; $sp^3d^2$ hybridized 
C. $[\text{CoF}_6]^{3-}$: Outer orbital complex; $d^2sp^3$ hybridized 
D. $[\text{FeF}_6]^{3-}$: Outer orbital complex; $sp^3d^2$ hybridized 
E. $[\text{Ni}(\text{CN})_4]^{2-}$: Inner orbital complex; $sp^3$ hybridized}

• A. A, B, C, D & E
• B. C & D Only
• C. A, B & D Only
• D. A, C & E Only

Hint:

Hybridization types: $d^2sp^3$ (Inner Octahedral), $sp^3d^2$ (Outer Octahedral), $dsp^2$ (Square Planar), $sp^3$ (Tetrahedral).

Answer 1

The Correct Option is C

A. $\text{Co}^{3+} (d^6)$, $\text{NH}_3$ is strong field. Low spin, inner orbital $d^2sp^3$. Correct.
B. $\text{Mn}^{3+} (d^4)$, $\text{Cl}^-$ is weak field. High spin, octahedral $sp^3d^2$. Correct.
C. $\text{Co}^{3+} (d^6)$, $\text{F}^-$ is weak field. High spin, octahedral $sp^3d^2$. Hybridization $d^2sp^3$ is incorrect here.
D. $\text{Fe}^{3+} (d^5)$, $\text{F}^-$ is weak field. High spin, octahedral $sp^3d^2$. Correct.
E. $\text{Ni}^{2+} (d^8)$, $\text{CN}^-$ is strong field. Low spin, square planar $dsp^2$. Hybridization $sp^3$ is incorrect.
Correct details are A, B, and D.