Question:

Identify the compound which has \(1^\circ\), \(2^\circ\), \(3^\circ\) and \(4^\circ\) carbons.

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Always count the number of carbon atoms directly attached to a carbon atom to determine whether it is primary, secondary, tertiary or quaternary.
Updated On: Jun 18, 2026
  • 2,2,3,3-Tetramethylpentane
  • 2,2-Dimethylpentane
  • 2,2,3-Trimethylpentane
  • 2-Methylpentane
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The Correct Option is C

Solution and Explanation

Concept: Classification of carbon atoms: \[ 1^\circ : \text{attached to one carbon} \] \[ 2^\circ : \text{attached to two carbons} \] \[ 3^\circ : \text{attached to three carbons} \] \[ 4^\circ : \text{attached to four carbons} \]

Step 1:
Examine 2,2,3-trimethylpentane.
Structure: \[ CH_3-C(CH_3)_2-CH(CH_3)-CH_2-CH_3 \] Here,
  • Terminal methyl groups are \(1^\circ\) carbons.
  • \(CH_2\) carbon is a \(2^\circ\) carbon.
  • \(CH\) carbon attached to three carbons is a \(3^\circ\) carbon.
  • Carbon at position-2 attached to four carbons is a \(4^\circ\) carbon.
Thus all four types are present. Hence, \[ \boxed{\text{2,2,3-Trimethylpentane}} \]
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