Question:
Identify reagents [A] and [B] in the following reactions of Salicylic acid.
Identify reagents [A] and [B] in the following reactions of Salicylic acid.
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Methyl salicylate is formed by esterification, while aspirin is formed by acetylation of salicylic acid.
Updated On: May 20, 2026
- A
- B
- C
- D
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The Correct Option is B
Solution and Explanation
Concept:
Salicylic acid contains both phenolic \(-OH\) and carboxylic acid \(-COOH\) functional groups and undergoes esterification and acetylation reactions.
Step 1: Reaction with methanol in acidic medium. Salicylic acid reacts with methanol in the presence of acid catalyst. \[ \mathrm{Salicylic\ acid + CH_3OH \rightarrow Methyl\ salicylate} \] Methyl salicylate is also known as oil of wintergreen. This is an esterification reaction involving the carboxylic acid group. Thus: \[ [A]=\mathrm{CH_3OH/H^+} \]
Step 2: Acetylation of phenolic group. The phenolic \(-OH\) group of salicylic acid reacts with acetic anhydride. \[ \mathrm{Salicylic\ acid + (CH_3CO)_2O \rightarrow Aspirin} \] The product formed is acetylsalicylic acid, commonly known as aspirin. Hence: \[ [B]=\mathrm{(CH_3CO)_2O/H^+} \]
Step 3: Conclusion. Therefore, option (2) is correct.
Step 1: Reaction with methanol in acidic medium. Salicylic acid reacts with methanol in the presence of acid catalyst. \[ \mathrm{Salicylic\ acid + CH_3OH \rightarrow Methyl\ salicylate} \] Methyl salicylate is also known as oil of wintergreen. This is an esterification reaction involving the carboxylic acid group. Thus: \[ [A]=\mathrm{CH_3OH/H^+} \]
Step 2: Acetylation of phenolic group. The phenolic \(-OH\) group of salicylic acid reacts with acetic anhydride. \[ \mathrm{Salicylic\ acid + (CH_3CO)_2O \rightarrow Aspirin} \] The product formed is acetylsalicylic acid, commonly known as aspirin. Hence: \[ [B]=\mathrm{(CH_3CO)_2O/H^+} \]
Step 3: Conclusion. Therefore, option (2) is correct.
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