Identify products A and B. $CH_3 - CH(CH_3) - CH_3 \xrightarrow{\text{dil. } KMnO_4, 273 K} A \xrightarrow{CrO_3} B$
Identify products A and B. $CH_3 - CH(CH_3) - CH_3 \xrightarrow{\text{dil. } KMnO_4, 273 K} A \xrightarrow{CrO_3} B$
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- A
- B
- C
- D
The Correct Option is A
Solution and Explanation
Step 2: $CrO_3$ is an oxidizing agent. However, tertiary alcohols are generally resistant to oxidation under these conditions. *Note: In many exam variants, if the starting material is an alkene, A would be a diol and B a ketone. For isobutane, A is tert-butanol.*
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