Identify product A and product B :
The Correct Option is D
Approach Solution - 1
In this problem, we need to identify the products formed in two different conditions of chlorination of benzene:
- \(\text{hv}\ (\text{light})\) condition leading to Product A
- \(\text{CCl}_4\) (in the presence of a solvent) condition leading to Product B
Step-by-step Explanation:
- In the presence of \(\text{hv}\ (\text{light})\) (Product A):
- When benzene reacts with chlorine under UV light, a substitution reaction occurs where a hydrogen atom is replaced by a chlorine atom.
- This process leads to the formation of chlorobenzene.
- In the presence of carbon tetrachloride \(\text{(CCl}_4\text{)}\)(Product B):
- Chlorination in the presence of \(\text{CCl}_4\) typically involves a side-chain chlorination of any alkyl group attached to the benzene ring. However, as pure benzene doesn’t have such a group, it's also likely that the context meant chlorobenzene formation or no reaction (commonly happens when the conditions or context is misread for pure benzene reactions).
- Conclusion:
- Product A is Chlorobenzene (as formed under light).
- Product B could typically again be interpreted in similar chlorobenzene contexts depending on exam setup. For this specific pattern, they could trick into redundant options or more detailed benzene derivatives' experimental setups.
Thus, matching interpretations logically, the correct answer identified previously in similar isinstance awareness setups would be
Answer: Product interpretation (semi-historically) over competition settings lands on priorities guided through similar exam situation setups.
Approach Solution -2
In this reaction:
- Product A is formed through a free radical mechanism. - Product B is formed through an electrophilic addition reaction on the alkene.
The correct answer is option (4), where Product A is formed by the free radical mechanism and Product B is formed by electrophilic addition in the presence of CCl4.
So, the correct answer is : Option (4).
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Organic Chemistry Questions
- Statement I: \([Ni(H_2O)_6]^{2+}\) is green in colour.
Statement II: \([Ni(ON)_4]^{2-}\) is colourless. - Which is following compound is easily attacked by electrophile?
- In chromatographic techniques, which of the following follows preferential adsorption?
- Column chromatography
- Thin layer chromatography
- Paper chromatography
- Which among the following halide/s will not show S$_N$1 reaction:
Choose the most appropriate answer from the options given below: - The major product(P) in the following reaction is
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.