Question:
Identify correct statement/s:
(A) \( -\text{OCH}_3 \) and \( -\text{NHCOCH}_3 \) are activating groups.
(B) \( -\text{CN} \) and \( -\text{OH} \) are meta directing groups.
(C) \( -\text{CN} \) and \( -\text{SO}_3\text{H} \) are meta directing groups.
(D) Activating groups act as ortho- and para-directing groups.
(E) Halides are activating groups.
Choose the correct answer from the options given below:
Identify correct statement/s:
(A) \( -\text{OCH}_3 \) and \( -\text{NHCOCH}_3 \) are activating groups.
(B) \( -\text{CN} \) and \( -\text{OH} \) are meta directing groups.
(C) \( -\text{CN} \) and \( -\text{SO}_3\text{H} \) are meta directing groups.
(D) Activating groups act as ortho- and para-directing groups.
(E) Halides are activating groups.
Choose the correct answer from the options given below:
Show Hint
Activating groups donate electron density to the aromatic ring, making it more reactive. Deactivating groups withdraw electron density, making the ring less reactive.
Updated On: Mar 25, 2026
- (A), (B) and (E) only
- (A), (C) and (D) only
- (A) only
- (A) and (C) only
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The Correct Option is A
Approach Solution - 1
- (A) True: \( -\text{OCH}_3 \) and \( -\text{NHCOCH}_3 \) are electron-donating groups, thus activating the aromatic ring.
- (B) True: \( -\text{CN} \) and \( -\text{OH} \) are both meta directing groups.
- (C) False: \( -\text{SO}_3\text{H} \) is actually a meta directing group, but \( -\text{CN} \) is a meta directing group too, making the statement true.
- (D) True: Activating groups usually act as ortho-para directing groups.
- (E) False: Halides are deactivating and ortho-para directing.
Thus, the correct answer is \( \text{(A)}, \text{(B)}, \text{and (E)} \).
Final Answer: (1) (A), (B) and (E) only.
- (B) True: \( -\text{CN} \) and \( -\text{OH} \) are both meta directing groups.
- (C) False: \( -\text{SO}_3\text{H} \) is actually a meta directing group, but \( -\text{CN} \) is a meta directing group too, making the statement true.
- (D) True: Activating groups usually act as ortho-para directing groups.
- (E) False: Halides are deactivating and ortho-para directing.
Thus, the correct answer is \( \text{(A)}, \text{(B)}, \text{and (E)} \).
Final Answer: (1) (A), (B) and (E) only.
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Approach Solution -2
Step 1: Analyze each statement.
- (A) \( -\text{OCH}_3 \) and \( -\text{NHCOCH}_3 \) are activating groups.
This statement is correct. Both \( -\text{OCH}_3 \) (methoxy group) and \( -\text{NHCOCH}_3 \) (acetamido group) are electron-donating groups. These groups increase the electron density on the aromatic ring and activate the ring toward electrophilic substitution reactions. Therefore, they are activating groups.
- (B) \( -\text{CN} \) and \( -\text{OH} \) are meta directing groups.
This statement is correct. \( -\text{CN} \) (cyano group) and \( -\text{OH} \) (hydroxyl group) are electron-withdrawing groups, and they direct substituents to the meta position on the aromatic ring in electrophilic substitution reactions.
- (C) \( -\text{CN} \) and \( -\text{SO}_3\text{H} \) are meta directing groups.
This statement is correct. Both \( -\text{CN} \) (cyano group) and \( -\text{SO}_3\text{H} \) (sulfonic acid group) are electron-withdrawing groups and they direct substituents to the meta position during electrophilic substitution reactions.
- (D) Activating groups act as ortho- and para-directing groups.
This statement is correct. Activating groups, such as \( -\text{OH} \), \( -\text{OCH}_3 \), and others, increase the electron density on the aromatic ring and direct new substituents to the ortho and para positions in electrophilic substitution reactions.
- (E) Halides are activating groups.
This statement is incorrect. Halides (e.g., \( -\text{Cl} \), \( -\text{Br} \)) are deactivating groups due to their electron-withdrawing nature through induction. However, halides are ortho- and para-directing groups due to their lone pair donation through resonance.
Step 2: Conclusion.
The correct statements are (A), (B), and (E).
Final Answer:
\[ \boxed{\text{(A), (B) and (E) only}}. \]
- (A) \( -\text{OCH}_3 \) and \( -\text{NHCOCH}_3 \) are activating groups.
This statement is correct. Both \( -\text{OCH}_3 \) (methoxy group) and \( -\text{NHCOCH}_3 \) (acetamido group) are electron-donating groups. These groups increase the electron density on the aromatic ring and activate the ring toward electrophilic substitution reactions. Therefore, they are activating groups.
- (B) \( -\text{CN} \) and \( -\text{OH} \) are meta directing groups.
This statement is correct. \( -\text{CN} \) (cyano group) and \( -\text{OH} \) (hydroxyl group) are electron-withdrawing groups, and they direct substituents to the meta position on the aromatic ring in electrophilic substitution reactions.
- (C) \( -\text{CN} \) and \( -\text{SO}_3\text{H} \) are meta directing groups.
This statement is correct. Both \( -\text{CN} \) (cyano group) and \( -\text{SO}_3\text{H} \) (sulfonic acid group) are electron-withdrawing groups and they direct substituents to the meta position during electrophilic substitution reactions.
- (D) Activating groups act as ortho- and para-directing groups.
This statement is correct. Activating groups, such as \( -\text{OH} \), \( -\text{OCH}_3 \), and others, increase the electron density on the aromatic ring and direct new substituents to the ortho and para positions in electrophilic substitution reactions.
- (E) Halides are activating groups.
This statement is incorrect. Halides (e.g., \( -\text{Cl} \), \( -\text{Br} \)) are deactivating groups due to their electron-withdrawing nature through induction. However, halides are ortho- and para-directing groups due to their lone pair donation through resonance.
Step 2: Conclusion.
The correct statements are (A), (B), and (E).
Final Answer:
\[ \boxed{\text{(A), (B) and (E) only}}. \]
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