Question:

Identify A in the following chemical reaction.

Show Hint

Intramolecular aldol condensation: the \(\alpha\)-carbon of one \(\mathrm{-CH_2CH_2CHO}\) chain attacks the CHO of the other chain; count the ring size formed.
Updated On: Nov 4, 2026
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The substrate is ortho-\(\mathrm{C_6H_4(CH_2CH_2CHO)_2}\).
Under NaOH in \(\mathrm{C_2H_5OH/H_2O}\) with heat an intramolecular aldol condensation occurs.
The only acidic C-H bonds are on the \(\alpha\)-carbon (the \(\mathrm{CH_2}\) next to CHO); the benzylic \(\mathrm{CH_2}\) is \(\beta\) and is not acidic.
The enolate carbon (\(\alpha\)-C) of chain 1 attacks the carbonyl carbon of chain 2. Atoms in the new ring: 2 aromatic carbons + benzylic C and \(\alpha\)-C of chain 1 + carbonyl C, \(\alpha\)-C and benzylic C of chain 2 = 7, so a seven-membered ring forms.
Dehydration (loss of \(\mathrm{H_2O}\)) gives the conjugated \(\alpha,\beta\)-unsaturated aldehyde: a benzo-fused cycloheptene carbaldehyde with the CHO on the C=C carbon. This is option (1).
Answer: (1) (benzo-fused seven-membered ring unsaturated aldehyde)
Was this answer helpful?
0
0