Identify [A], [B], and [C], respectively in the following reaction sequence : 





To identify the compounds [A], [B], and [C] in the given reaction sequence, let's analyze each step of the reaction.
Step 1: The first reaction involves the treatment of [A] with \(\text{NaNO}_2\) and \(\text{HCl}\) at 273–278 K.
This is a typical diazotization reaction where an aromatic amine (aniline) is converted into a diazonium salt. Thus, [A] is aniline, \(\text{C}_6\text{H}_5\text{NH}_2\).
Step 2: The diazonium salt formed reacts with KI.
This is a Sandmeyer reaction where the diazonium group is replaced by iodide to form an iodobenzene compound. Hence, [B] is iodobenzene, \(\text{C}_6\text{H}_5\text{I}\).
Step 3: The compound undergoes a reaction with 2Na in dry ether.
This reaction is a typical Wurtz reaction where iodobenzene reacts with sodium to form biphenyl. Therefore, [C] is biphenyl, \(\text{C}_6\text{H}_5\text{-C}_6\text{H}_5\).
The complete reaction sequence can be summarized as follows:
From the given options, the correct identification of [A], [B], and [C] is as follows:
Thus, the correct answer is: Aniline ([A]) → Iodobenzene ([B]) → Biphenyl ([C]).





Consider the following reaction of benzene. the percentage of oxygen is _______ %. (Nearest integer) 
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______. 
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.