Question

(i) If z = 10, find the value of z³ – 3(z – 10) 
(ii) If p = – 10, find the value of p² – 2p – 100

Answer 1

(i) z³–3(z–10) = (10)³-3(10-10) = 1000-3×0=1000-0 = 1000 [putting z=10]
(ii) p²–2p–100 = (-10)²-2(-10)-100 = 100+20-100 = 20 [putting p=-10]

Answer 2

(i) Given z=10

We need to find the value of \(z^3 - 3(z - 10)\)
First, simplify the expression:
\(z^3 - 3(z - 10) = z^3 - 3z + 30\)
Now, substitute \(z=10:\)
\((10)^3 - (3 \times 10) + 30 = 1000 - 30 + 30 = 1000\)
So, the required value is 1000.

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(ii) Given \(p=−10\)
We need to find the value of \(p^2 - 2p - 100.\)
Substitute p=−10 into the expression:
\((-10)^2 - 2 \times (-10) - 100 = 100 + 20 - 100 = 20\)
So, the required value is 20.