Hydrogen peroxide reacts with iodine in basic medium to give :
Show Hint
- \(\mathrm{IO_4^-}\)
- \(\mathrm{IO^-}\)
- \(\mathrm{I^-}\)
- \(\mathrm{IO_3^-}\)
The Correct Option is C
Solution and Explanation
\(\mathrm{H_2O_2 + I_2 + 2OH^- \to 2I^- + 2H_2O + O_2}\).
(In acidic medium the reverse happens: H\(_2\)O\(_2\) oxidises I\(^-\) to I\(_2\).)
The iodine-containing product is I\(^-\).
Answer: (3) \(\mathrm{I^-}\)
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