Question:

How many trailing zeros are there at the end of \(25!\) ?

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Trailing zeros come from pairs of 2 and 5 in the factorization; since 2s are far more plentiful in 25!, just count how many multiples of 5 (and multiples of 25) lie between 1 and 25.
Updated On: Jul 8, 2026
  • 4
  • 5
  • 7
  • 6
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The Correct Option is D

Solution and Explanation

Number of trailing zeros \(=\) number of factors of 5 \(=\left\lfloor\frac{25}{5}\right\rfloor+\left\lfloor\frac{25}{25}\right\rfloor=5+1=6\). Correct option: 6.
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