Question:
How many grams of metallic mercury could be produced approximately by electrolysing a \(1.0\,\mathrm{M}\) \(\mathrm{Hg(NO_3)_2}\) solution with a current of \(2.0\,\mathrm{A}\) for \(3.0\,\mathrm{h}\)?
\[ \begin{aligned} &\text{Given:} \\ &\text{Molar mass of Hg} = 200\,\mathrm{g\,mol^{-1}},\\ &F = 96500\,\mathrm{C\,mol^{-1}} \end{aligned} \]
How many grams of metallic mercury could be produced approximately by electrolysing a \(1.0\,\mathrm{M}\) \(\mathrm{Hg(NO_3)_2}\) solution with a current of \(2.0\,\mathrm{A}\) for \(3.0\,\mathrm{h}\)?
\[ \begin{aligned} &\text{Given:} \\ &\text{Molar mass of Hg} = 200\,\mathrm{g\,mol^{-1}},\\ &F = 96500\,\mathrm{C\,mol^{-1}} \end{aligned} \]
Show Hint
Faraday's first law:
\[
\boxed{
m=\frac{MQ}{nF}
=\frac{MIt}{nF}.
}
\]
Here, \(n\) is the number of electrons involved in the electrode reaction.
Updated On: Jul 21, 2026
- \(22.4\,\mathrm{g}\)
- \(20.1\,\mathrm{g}\)
- \(11.2\,\mathrm{g}\)
- \(40.2\,\mathrm{g}\)
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Calculate the quantity of electricity passed.
Using
\[
Q=It,
\]
\[
Q=2\times(3\times3600)
=21600\ \mathrm{C}.
\]
Step 2: Apply Faraday's law of electrolysis. The cathode reaction is \[ \mathrm{Hg^{2+}+2e^-\rightarrow Hg.} \] Hence, \[ n=2. \] Mass deposited is \[ m=\frac{MQ}{nF}, \] where \[ M=200\ \mathrm{g\,mol^{-1}}. \] Therefore, \[ m = \frac{200\times21600}{2\times96500} \approx22.4\ \mathrm{g}. \]
Step 3: State the answer. Thus, \[ \boxed{22.4\ \mathrm{g}} \] of mercury is deposited. Therefore, the correct option is \(\boxed{(A)}\).
Step 2: Apply Faraday's law of electrolysis. The cathode reaction is \[ \mathrm{Hg^{2+}+2e^-\rightarrow Hg.} \] Hence, \[ n=2. \] Mass deposited is \[ m=\frac{MQ}{nF}, \] where \[ M=200\ \mathrm{g\,mol^{-1}}. \] Therefore, \[ m = \frac{200\times21600}{2\times96500} \approx22.4\ \mathrm{g}. \]
Step 3: State the answer. Thus, \[ \boxed{22.4\ \mathrm{g}} \] of mercury is deposited. Therefore, the correct option is \(\boxed{(A)}\).
Was this answer helpful?
0
0
Top TS EAMCET Chemistry Questions
- A, B and C are three biomolecules. The results of the tests performed on them are given below :A, B and C are respectively :
Molisch's lest Barfoed Test Biuret Test A Positive Negative Negativde B Positive Positive Negative C Negative Negative Positive - 1 mole of $H_2$ and 2 moles of $I_2$ are taken initially in a 2 litre vessel. The number of moles of $H_2$ at equilibrium is 0.2. Then the number of moles of $I_2$ and HI at equilibrium is
- The pH of a buffer containing equal molarconcentration of a weak base and its chloride ( $K_b$ for weak base = $2 \times 10^{-5}$, log 2 = 0.3) is
- Atomic radius (pm) of Al, Si, N and F respectively is
- Consider the following electrode process of a cell, $ {Cl^{-1} -> \frac{1}{2} Cl_2 + e^{-}}$ $ {[MCl + e^{-} -> M + Cl^{-} ] }$ If EMF of this cell is $-1.140\, V$ and $E^0$ value of the cell is $-0.55\,V$ at $298\,K$, the value of the equilibrium constant of the sparingly soluble salt MCl is in the order of
View More Questions
Top TS EAMCET Physical Chemistry Questions
- The RMS velocity of dihydrogen is \( \sqrt{7} \) times more than that of dinitrogen. If \( T_{\text{H}_2} \) and \( T_{\text{N}_2} \) are the temperatures of dihydrogen and dinitrogen, then the correct relationship between them is
- For the reaction \( \text{N}_2\text{O}_4(g) \rightleftharpoons 2\text{NO}_2(g) \), the correct relation between degree of dissociation (\(\alpha\)) of \( \text{N}_2\text{O}_4(g) \) and equilibrium constant, \( K_p \) is (P = total pressure of mixture)
- A substance has a density of \( 2 \, \text{g cm}^{-3} \). It crystallizes in the fcc crystal with an edge length of 600 pm. The molar mass of the substance (in \( \text{g mol}^{-1} \)) is (\( N_A = 6 \times 10^{23} \, \text{mol}^{-1} \))
- Observe the following statements.
Statement - I: The boiling point of 0.1 M urea solution is less than that of 0.1 M KCl solution.
Statement - II: Elevation of boiling point is inversely proportional to molar mass of solute.
The correct answer is - At 298 K, if emf of the cell corresponding to the reaction, \( \text{Zn(s)} + 2\text{H}^+ \text{(aq)} \to \text{Zn}^{2+} (0.01 \text{ M}) + \text{H}_2 \text{(g)} \) (1 atm) is 0.28 V, then the pH of the solution at the hydrogen electrode is \( \left( \frac{2.303 RT}{F} = 0.06 \text{ V} \right) \), \( E^0_{\text{Zn}^{2+}|\text{Zn}} = -0.76 \text{ V} \)
View More Questions
Top TS EAMCET Questions
- A bag contains $5$ red balls, $3$ black balls and $4$ white balls are drawn at random. The probability that they are not of same colour is
- If $cosec\, \theta - \cot \theta = 2017$, then quadrant in which $\theta $ lies is
- If $a$ is a unit vector, then $| a \times \hat{ i }|^{2}+| a \times \hat{ j }|^{2}+| a \times \hat{ k }|^{2}=$
- $A$ straight line makes an intercept on the $Y$-axis twice as long as that on $X$-axis and is at a unit distance from the origin. Then the line is represented by the equations
- Let $S$ and $S'$ be the foci of an ellipse and B be one end of its minor axis. If $SBS'$ is an isosceles right angled triangle then the eccentricity of the ellipse is
View More Questions