Question:

How many faradays of electricity are required to produce $12\,\mathrm{g}$ of magnesium from molten $\mathrm{MgCl_2}$?} \[ (\text{Atomic weight of Mg}=24\,\mathrm{g\,mol^{-1}}) \]

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Number of Faradays required \[ =\text{Moles of metal}\times\text{Valency}. \]
Updated On: Jun 17, 2026
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The Correct Option is A

Solution and Explanation

Concept: One faraday corresponds to one mole of electrons. During electrolysis, \[ \mathrm{Mg}^{2+}+2e^-\rightarrow \mathrm{Mg}. \] Thus one mole of magnesium requires two faradays.

Step 1:
Calculate moles of magnesium. \[ \text{Moles of Mg} = \frac{12}{24} = 0.5. \]

Step 2:
Determine electron requirement. One mole Mg requires \[ 2F. \] Therefore \[ 0.5\ \text{mol Mg} \] requires \[ 0.5\times2=1F. \]

Step 3:
Final answer. \[ \boxed{1\ \text{Faraday}} \]
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