Given
In the above compounds correct order of reactivity in electrophilic substitution reactions will be:
Given
In the above compounds correct order of reactivity in electrophilic substitution reactions will be:
Show Hint
- \(\mathrm{B} \gt \mathrm{A} \gt \mathrm{C} \gt \mathrm{D}\)
- \(\mathrm{D} \gt \mathrm{C} \gt \mathrm{B} \gt \mathrm{A}\)
- \(\mathrm{A} \gt \mathrm{B} \gt \mathrm{C} \gt \mathrm{D}\)
- \(\mathrm{B} \gt \mathrm{C} \gt \mathrm{A} \gt \mathrm{D}\)
The Correct Option is A
Solution and Explanation
\(\mathrm{-CH_3}\) is electron donating (+I, hyperconjugation): it activates the ring, so B is more reactive than benzene.
-Cl withdraws electrons by -I more than it donates by +M: it deactivates the ring, so C is less reactive than benzene.
\(\mathrm{-NO_2}\) is a strong -I, -M group: strongest deactivation, so D is least reactive.
Order: B > A > C > D.
Answer: (1) \(\mathrm{B} \gt \mathrm{A} \gt \mathrm{C} \gt \mathrm{D}\)
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