Question:

Given below are two statements :
Statement I : Potassium permanganate on heating at 573K forms potassium manganate.
Statement II : Both potassium permanganate and potassium manganate are tetrahedral and paramagnetic in nature.
In the light of the above statements, choose the most appropriate answer from the options given below :

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Heating \(\mathrm{KMnO_4}\) gives \(\mathrm{K_2MnO_4}\); but \(\mathrm{MnO_4^-}\) (Mn VII, \(d^0\)) is diamagnetic while \(\mathrm{MnO_4^{2-}}\) (Mn VI, \(d^1\)) is paramagnetic.
Updated On: Nov 4, 2026
  • Statement I is true but statement II is false
  • Statement I is false but statement II is true
  • Both statement I and statement II are false
  • Both statement I and statement II are true
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The Correct Option is A

Solution and Explanation

Statement I: \(2\mathrm{KMnO_4}\xrightarrow{\Delta,\ 573\ \mathrm{K}}\mathrm{K_2MnO_4}+\mathrm{MnO_2}+\mathrm{O_2}\), so potassium manganate is formed. True.
Statement II: both ions are tetrahedral, but \(\mathrm{MnO_4^-}\) has Mn in +7 state (\(3d^0\), no unpaired electron, diamagnetic) whereas \(\mathrm{MnO_4^{2-}}\) has Mn in +6 (\(3d^1\), one unpaired electron, paramagnetic). Permanganate is not paramagnetic, so Statement II is false.
Hence Statement I is true and Statement II is false.
Answer: (1) Statement I is true but statement II is false
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