To evaluate the given statements, let's analyze each one and verify its accuracy based on chemical concepts.
Based on the above analysis, Statement (I) is incorrect because non-metals are not present in the d-block of the periodic table.
Hence, Statement (II) is true, as it correctly describes the general trend for non-metals compared to metals regarding ionisation enthalpy and electronegativity.
Based on the above analysis, the most appropriate answer is: Statement I is false but Statement II is true.
Analysis of Statement (I): - The p-block elements contain both metals, non-metals, and metalloids. Examples include elements such as carbon (non-metal), lead (metal), and silicon (metalloid). - However, the d-block elements primarily consist of transition metals and do not contain non-metals. Therefore, it is incorrect to state that both metals and non-metals exist in the d-block.
- Hence, Statement (I) is false.
Analysis of Statement (II): - Non-metals generally have higher ionisation enthalpy and higher electronegativity than metals. This is due to the strong nuclear attraction for electrons in non-metals, making it more difficult to remove electrons (higher ionisation energy) and more favorable to gain electrons (higher electronegativity).
- Therefore, Statement (II) is true.
Conclusion: Statement I is false but Statement II is true.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)