Question:

Given below are two statements :
Statement I : 2-methylbutane on oxidation with \(\mathrm{KMnO_4}\) gives 2-methylbutan-2-ol.
Statement II : n-alkanes can be easily oxidised to corresponding alcohols with \(\mathrm{KMnO_4}\).
Choose the correct option :

Show Hint

Tertiary C-H bonds are oxidised by KMnO4 to alcohols; ordinary n-alkanes are not easily oxidised.
Updated On: Nov 4, 2026
  • Both statement I and statement II are incorrect
  • Both statement I and statement II are correct
  • Statement I is correct but statement II is incorrect
  • Statement I is incorrect but statement II is correct
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Statement I: 2-methylbutane \(\mathrm{(CH_3)_2CHCH_2CH_3}\) has a tertiary C-H bond. Oxidation with \(\mathrm{KMnO_4}\) replaces this tertiary hydrogen by OH, giving 2-methylbutan-2-ol. Correct.
Statement II: n-alkanes have only primary and secondary C-H bonds, which are not easily oxidised by \(\mathrm{KMnO_4}\) to the corresponding alcohols (they need special conditions and give mixtures). Incorrect.
Answer: (3) Statement I is correct but statement II is incorrect
Was this answer helpful?
0
0