In an Ellingham diagram, a negative slope indicates that the reaction becomes more favorable at higher temperatures, while a positive slope indicates that the reaction becomes less favorable.
Assertion A is correct: In an Ellingham diagram, the oxidation of carbon to carbon monoxide does indeed show a negative slope, indicating that the reaction becomes more favorable as temperature increases.
Reason R is incorrect: While CO is a reducing agent, it does not tend to decompose at higher temperatures; rather, the decomposition of CO to C and \( \text{O}_2 \) is unfavorable at high temperatures, as shown by its position on the Ellingham diagram.
Conclusion: The correct answer is 4.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Minerals are the naturally occurring, homogeneous inorganic solid substances. They are having a definite chemical composition and crystalline structure, hardness and color. For example, copper pyrite, calamine, etc.

Impurities in an ore are called gauge. The removal of a gauge from the ore is called concentration ore.
Several steps are involved in the extraction of pure metal from ores. Major steps are as follows –