Solution:
Assertion A: 5f electrons can participate in bonding to a far greater extent than 4f electrons.
This assertion is true. 5f electrons, being more spatially extended, have greater interaction with ligand orbitals and thus participate in bonding to a greater extent compared to the more buried 4f electrons.
Reason R: 5f orbitals are not as buried as 4f orbitals.
This reason is also true. 5f orbitals extend further into space than 4f orbitals, meaning they are less shielded by inner electrons and are more available for bonding.
Furthermore, the Reason R directly explains Assertion A. Because 5f orbitals are less buried, they are more available for bonding, which is why 5f electrons participate in bonding to a far greater extent than 4f electrons.
Therefore, both A and R are true, and R is the correct explanation of A.
Correct Answer: (2) Both A and R are true and R is the correct explanation of A.
Given below are the quantum numbers for 4 electrons.
A. n=3, l=2, ml=1,ms=+\(\frac{1}{2}\)
B. n=4, l=1, ml=0,ms=+\(\frac{1}{2}\)
C. n=4, l=2, ml=–2,ms=–\(\frac{1}{2}\)
D. n=3, l=1, ml=–1,ms=+\(\frac{1}{2}\)
The correct order of increasing energy is
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]