Given below arc two statements:
Statement I : In the metallurgy process. sulphide ore is converted to oxide before reduction.
Statement II : Oxide ores in general are easier to reduce.
In the light of the above statements, choose the most appropriate answer from the options given below
Statement I : In the metallurgy process. sulphide ore is converted to oxide before reduction.
Statement II : Oxide ores in general are easier to reduce.
In the light of the above statements, choose the most appropriate answer from the options given below
- Both Statement I and Statement II are correct
- Statement I is correct but Statement II is incorrect
- Statement I is incorrect but Statement II is correct
- Both Statement I and Statement II are incorrect
The Correct Option is A
Solution and Explanation
Statement I:
Sulphide ores are converted to oxides before reduction. This process is called roasting. For example:
\[ 2\text{ZnS} + 3\text{O}_2 \rightarrow 2\text{ZnO} + 2\text{SO}_2 \]
This statement is true.
Statement II:
Oxide ores are generally easier to reduce than sulphide ores. This can be explained by the following:
- During the carbon reduction of oxides, \( \text{CO}_2 \) is produced, which is a gas that readily escapes. This drives the reaction forward more easily.
- In contrast, the carbon reduction of sulphides produces \( \text{CS}_2 \), which is less volatile than \( \text{CO}_2 \) due to stronger intermolecular forces caused by sulfur being larger than oxygen.
The reaction for sulphide reduction is:
\[ 2\text{MS} + \text{C} \rightarrow 2\text{M} + \text{CS}_2 \]
Since \( \text{CO}_2 \) is more volatile compared to \( \text{CS}_2 \), oxide reduction is favored. This statement is also true.
Conclusion:
Final Answer: Both Statement I and Statement II are correct.
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