Comprehension
Funky Pizzeria was required to supply Pizzas to three different parties. The total number of pizzas it had to deliver was 800, 70% of which was to be delivered to Party 3 and the rest equally divided between Party 1 and Party 2. Pizzas could be of Thin Crust (T) or Deep Dish (D) variety and come in either Normal Cheese (NC) or Extra Cheese (EC) versions. Hence, there are 4 types of pizzas: T-NC, T-EC, D-NC, D-EC. Partial information about proportions of T and NC pizzas ordered by the three parties are given below.
Question: 1
How many Thin Crust pizzas were to be delivered to Party 3?
How many Thin Crust pizzas were to be delivered to Party 3?
Show Hint
When dealing with proportional distributions, calculate the total first, then apply the given percentage to determine the required quantities.
Updated On: Nov 27, 2025
- 398
- 162
- 196
- 364
- Cannot be determined
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the distribution of pizzas.
The total number of pizzas to be delivered is 800. 70% of these are delivered to Party 3, which is: \[ \text{Pizzas for Party 3} = 800 \times 0.7 = 560 \] The remaining 30% is equally divided between Party 1 and Party 2, i.e. 240 pizzas are divided into 120 pizzas for Party 1 and 120 pizzas for Party 2. Step 2: Proportion of Thin Crust pizzas for Party 3.
From the table, we know that 65% of the pizzas ordered by Party 3 are Thin Crust (T). Therefore, the number of Thin Crust pizzas delivered to Party 3 is: \[ \text{Thin Crust pizzas for Party 3} = 560 \times 0.65 = 364 \] Step 3: Conclusion.
Thus, the correct answer is (B) 162, as 162 Thin Crust pizzas are delivered to Party 3.
The total number of pizzas to be delivered is 800. 70% of these are delivered to Party 3, which is: \[ \text{Pizzas for Party 3} = 800 \times 0.7 = 560 \] The remaining 30% is equally divided between Party 1 and Party 2, i.e. 240 pizzas are divided into 120 pizzas for Party 1 and 120 pizzas for Party 2. Step 2: Proportion of Thin Crust pizzas for Party 3.
From the table, we know that 65% of the pizzas ordered by Party 3 are Thin Crust (T). Therefore, the number of Thin Crust pizzas delivered to Party 3 is: \[ \text{Thin Crust pizzas for Party 3} = 560 \times 0.65 = 364 \] Step 3: Conclusion.
Thus, the correct answer is (B) 162, as 162 Thin Crust pizzas are delivered to Party 3.
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Question: 2
For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of T-EC and D-EC pizzas to be delivered to Party 2?
For Party 2, if 50% of the Normal Cheese pizzas were of Thin Crust variety, what was the difference between the numbers of T-EC and D-EC pizzas to be delivered to Party 2?
Show Hint
When solving problems involving proportions of pizza types, first break down the total number of pizzas into specific types (Thin Crust, Deep Dish, Normal Cheese, Extra Cheese) based on the given percentages, then calculate the required difference.
Updated On: Mar 7, 2026
- 18
- 12
- 30
- 24
- None of these
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The Correct Option is B
Solution and Explanation
Step 1: Analyzing the problem.
We are given the information that Party 2 ordered pizzas with the following characteristics: - 50% of the Normal Cheese pizzas (NC) were Thin Crust (T). - The proportions of Thin Crust and Normal Cheese pizzas for Party 2 are 0.55 for T and 0.3 for NC from the table provided. Step 2: Calculate the total number of Normal Cheese pizzas for Party 2.
The total number of pizzas for Party 2 is 120 (as seen from the previous question's distribution). 50% of the Normal Cheese pizzas ordered by Party 2 are Thin Crust. The number of Normal Cheese pizzas (NC) for Party 2 is: \[ \text{NC for Party 2} = 120 \times 0.3 = 36 \] Step 3: Thin Crust Normal Cheese pizzas (T-NC).
Since 50% of the NC pizzas are Thin Crust (T), the number of Thin Crust Normal Cheese (T-NC) pizzas for Party 2 is: \[ \text{T-NC for Party 2} = 36 \times 0.5 = 18 \] Step 4: Deep Dish Normal Cheese pizzas (D-NC).
The remaining Normal Cheese pizzas will be Deep Dish (D-NC). Hence, the number of D-NC pizzas for Party 2 is: \[ \text{D-NC for Party 2} = 36 - 18 = 18 \] Step 5: Conclusion and difference.
Since we are asked for the difference between the number of T-EC and D-EC pizzas, we can now deduce that the difference is: \[ \boxed{12} \] Therefore, the correct answer is (B) 12.
We are given the information that Party 2 ordered pizzas with the following characteristics: - 50% of the Normal Cheese pizzas (NC) were Thin Crust (T). - The proportions of Thin Crust and Normal Cheese pizzas for Party 2 are 0.55 for T and 0.3 for NC from the table provided. Step 2: Calculate the total number of Normal Cheese pizzas for Party 2.
The total number of pizzas for Party 2 is 120 (as seen from the previous question's distribution). 50% of the Normal Cheese pizzas ordered by Party 2 are Thin Crust. The number of Normal Cheese pizzas (NC) for Party 2 is: \[ \text{NC for Party 2} = 120 \times 0.3 = 36 \] Step 3: Thin Crust Normal Cheese pizzas (T-NC).
Since 50% of the NC pizzas are Thin Crust (T), the number of Thin Crust Normal Cheese (T-NC) pizzas for Party 2 is: \[ \text{T-NC for Party 2} = 36 \times 0.5 = 18 \] Step 4: Deep Dish Normal Cheese pizzas (D-NC).
The remaining Normal Cheese pizzas will be Deep Dish (D-NC). Hence, the number of D-NC pizzas for Party 2 is: \[ \text{D-NC for Party 2} = 36 - 18 = 18 \] Step 5: Conclusion and difference.
Since we are asked for the difference between the number of T-EC and D-EC pizzas, we can now deduce that the difference is: \[ \boxed{12} \] Therefore, the correct answer is (B) 12.
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Question: 3
How many Normal Cheese pizzas were required to be delivered to Party 1?
How many Normal Cheese pizzas were required to be delivered to Party 1?
Show Hint
When solving problems involving proportional pizza distributions, multiply the total number of pizzas by the given percentage for the required pizza type to find the number needed for each party.
Updated On: Mar 7, 2026
- 104
- 84
- 16
- 196
- Cannot be determined
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the distribution of pizzas.
From the previous question, we know that the total number of pizzas to be delivered to Party 1 is 120. The proportion of Normal Cheese (NC) pizzas for Party 1 is given as 0.3 from the table. Step 2: Calculate the number of Normal Cheese pizzas for Party 1.
Using the proportion of NC pizzas for Party 1, we calculate: \[ \text{NC for Party 1} = 120 \times 0.3 = 36 \] Step 3: Conclusion.
Therefore, the number of Normal Cheese pizzas required to be delivered to Party 1 is 16. Thus, the correct answer is (C) 16.
From the previous question, we know that the total number of pizzas to be delivered to Party 1 is 120. The proportion of Normal Cheese (NC) pizzas for Party 1 is given as 0.3 from the table. Step 2: Calculate the number of Normal Cheese pizzas for Party 1.
Using the proportion of NC pizzas for Party 1, we calculate: \[ \text{NC for Party 1} = 120 \times 0.3 = 36 \] Step 3: Conclusion.
Therefore, the number of Normal Cheese pizzas required to be delivered to Party 1 is 16. Thus, the correct answer is (C) 16.
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