Question:

From the graph of angle of deviation versus angle of incidence for an equilateral prism, the refractive index of material of prism is

Show Hint

For an equilateral prism, if the minimum deviation is also equal to the prism angle (\( \delta_m = A = 60^\circ \)), the refractive index will always evaluate to \( \sqrt{3} \). Note that in this state, the angle of incidence \( i \) also equals \( 60^\circ \).
Updated On: Apr 23, 2026
  • \( \frac{\sqrt{3}}{2} \)
  • \( \frac{3}{2} \)
  • \( \sqrt{3} \)
  • \( \sqrt{2} \)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
The question asks us to calculate the refractive index of a prism's material based on a given graph of angle of deviation (\( \delta \)) vs. angle of incidence (\( i \)) for an equilateral prism.
Step 2: Key Formula or Approach:
The refractive index (\( n \)) of a prism can be determined using the prism formula:
\[ n = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)} \]
Where:
- \( A \) is the angle of the prism.
- \( \delta_m \) is the angle of minimum deviation.
Step 3: Detailed Explanation:
1. Determine the Prism Angle (\( A \)):
An "equilateral prism" has all its internal angles equal to \( 60^\circ \). Therefore, the angle of the prism \( A = 60^\circ \).
2. Identify the Minimum Deviation (\( \delta_m \)) from the graph:
The graph shows how the deviation changes with the angle of incidence. The lowest point on the U-shaped curve represents the condition of minimum deviation.
Looking at the graph, the coordinates of the minimum point are \( (i, \delta) = (60^\circ, 60^\circ) \).
Thus, the angle of minimum deviation \( \delta_m = 60^\circ \).
3. Calculation of Refractive Index (\( n \)):
Substitute the values \( A = 60^\circ \) and \( \delta_m = 60^\circ \) into the formula:
\[ n = \frac{\sin\left(\frac{60^\circ + 60^\circ}{2}\right)}{\sin\left(\frac{60^\circ}{2}\right)} \]
\[ n = \frac{\sin(60^\circ)}{\sin(30^\circ)} \]
Using known trigonometric values: \( \sin(60^\circ) = \frac{\sqrt{3}}{2} \) and \( \sin(30^\circ) = \frac{1}{2} \).
\[ n = \frac{\sqrt{3}/2}{1/2} = \sqrt{3} \]
Step 4: Final Answer:
The refractive index of the prism material is \( \sqrt{3} \), which corresponds to option (C).
Was this answer helpful?
0
1