Question:
From the given information, calculate enthalpy of formation of 2 moles of $C_6H_6$(l) at 25°C. Given: $CH(C_6H_6$(l)) = –3264.6 kJ/mol $CH(C(s))$ = –393.5 kJ/mol $fH(H_2O(l))$ = –285.83 kJ/mol
From the given information, calculate enthalpy of formation of 2 moles of $C_6H_6$(l) at 25°C. Given: $CH(C_6H_6$(l)) = –3264.6 kJ/mol $CH(C(s))$ = –393.5 kJ/mol $fH(H_2O(l))$ = –285.83 kJ/mol
Updated On: Feb 25, 2026
- –124.5 kJ/mol
- –46.11 kJ/mol
- 46.11 kJ/mol
- 124.5 kJ/mol
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The Correct Option is C
Solution and Explanation
The Correct answer is option is (C) : 46.11 kJ/mol
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