Question:
Free energy change for vaporization of pure substance is
Free energy change for vaporization of pure substance is
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Equilibrium = $\Delta G$ is 0. Phase changes at their specific points are equilibrium states.
Updated On: Jul 4, 2026
- Unity
- Positive
- Zero at boiling point
- Negative
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The Correct Option is C
Solution and Explanation
Step 1: Concept
Gibbs free energy change ($\Delta G$) determines the spontaneity and equilibrium of a process.
Step 2: Meaning
Vaporization is a phase change where liquid and gas exist together.
Step 3: Analysis
At the standard boiling point, the liquid and vapor phases are in equilibrium. For any system at equilibrium at constant temperature and pressure, the change in Gibbs free energy is zero.
Step 4: Conclusion
Thus, for the vaporization of a pure substance, $\Delta G$ is zero exactly at the boiling point. Final Answer: (C)
Gibbs free energy change ($\Delta G$) determines the spontaneity and equilibrium of a process.
Step 2: Meaning
Vaporization is a phase change where liquid and gas exist together.
Step 3: Analysis
At the standard boiling point, the liquid and vapor phases are in equilibrium. For any system at equilibrium at constant temperature and pressure, the change in Gibbs free energy is zero.
Step 4: Conclusion
Thus, for the vaporization of a pure substance, $\Delta G$ is zero exactly at the boiling point. Final Answer: (C)
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