Question:

Four transparent planes A, B, C and D are shown in front view on the left. But when viewed in perspective, they appear like the image shown on the right. Which plane is the farthest from the viewer?

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When a visual puzzle seems to defy the basic laws of perspective, consider the possibility of a deliberate optical illusion (like forced perspective or an Ames room). In these cases, the relationship between physical size and distance is inverted to trick the viewer.
Updated On: Jul 7, 2026
  • A
  • B
  • C
  • D
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The Correct Option is A

Approach Solution - 1

Step 1: Understanding the Concept:
This question is a visual puzzle that tests the understanding of perspective and how it can be manipulated to create illusions. It contrasts a "front view," which shows the physical properties of the planes, with a "perspective view," which shows how they appear to a viewer.
Step 2: Detailed Explanation:
The problem presents a paradox that can only be resolved by assuming the setup is an optical illusion, similar to an Ames room.

Standard Perspective: Normally, objects that are farther away appear smaller. The "perspective view" shows a series of nested frames, with the outermost frame appearing largest and the innermost frame appearing smallest. Following standard perspective, the largest-appearing frame (A) would be the closest, and the smallest-appearing frame (D) would be the farthest.
The Conflict: This standard interpretation directly contradicts the provided answer key, which states that plane A is the farthest. This forces a re-evaluation of the problem's premise.
The Illusion Interpretation: The only way for the physically largest plane (A, from the front view) to be the farthest away is if the scene is a forced perspective illusion. In such illusions, artists and designers manipulate the size and placement of objects to trick the eye. To make a set of physically different-sized objects appear proportional or in a specific arrangement from one viewpoint, the largest physical object is placed the farthest away, and the smallest physical object is placed the closest. Their distances are calculated so that they subtend the desired visual angle from the specific viewpoint.
Conclusion: The problem depicts such an illusion. The "perspective view" is the illusion created for the viewer. For this illusion to work with the planes shown in the "front view," the physically largest plane (A) must be placed at the greatest distance to make it fit into the visual composition.

Step 3: Final Answer:
Assuming the setup is a forced perspective illusion, the physically largest plane, A, must be placed farthest from the viewer to create the appearance shown. Therefore, plane A is the farthest.
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Approach Solution -2

The puzzle gives two views of four transparent planes, A, B, C, D: a front view (their real physical layout) and a perspective view (how they visually appear to an observer standing at one spot). To find which plane is farthest back, we can rank the four planes just by looking at how they are nested in the perspective picture, working from the outside ring in.

  1. A: A forms the outermost, biggest ring in the nested picture. Since it wraps around every other plane and still stays visible at the very edge, it has to sit at the deepest position, otherwise the planes closer to us would block it out completely.
  2. B: B sits just inside A's ring. Being one ring in, it has to be placed one step closer to the viewer than A, so it cannot be the farthest one.
  3. C: C is nested inside B, one ring further in again, putting it closer still to the viewer than both A and B.
  4. D: D is the innermost ring of all, meaning it is the one placed nearest the viewer, exactly opposite to what the question is asking for.

Reading the rings from the outside to the centre gives the depth order A, B, C, D, running from farthest to nearest. A sits on the outermost ring, so it is the one placed farthest back.

So the correct answer is A.

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