For x ∈ (0, π), the equation sin x + 2sin2x −sin3x = 3 has
For x ∈ (0, π), the equation sin x + 2sin2x −sin3x = 3 has
Infinitely many solutions
Three solutions
One solution
No solution
The Correct Option is D
Solution and Explanation
The correct answer is option D) No solution
The least value of R.H.S is 3 at x = π/2 while the greatest value of L.H.S is 3 at x = π/3.
Hence, L.H.S and R.H.S are not equal at the same value of x. so, no solution
Top Questions on Trigonometric Identities
If \[ \frac{\cos^2 48^\circ - \sin^2 12^\circ}{\sin^2 24^\circ - \sin^2 6^\circ} = \frac{\alpha + \beta\sqrt{5}}{2}, \] where \( \alpha, \beta \in \mathbb{N} \), then the value of \( \alpha + \beta \) is ___________.
- JEE Main - 2026
- Mathematics
- Trigonometric Identities
If $\cot x=\dfrac{5}{12}$ for some $x\in(\pi,\tfrac{3\pi}{2})$, then \[ \sin 7x\left(\cos \frac{13x}{2}+\sin \frac{13x}{2}\right) +\cos 7x\left(\cos \frac{13x}{2}-\sin \frac{13x}{2}\right) \] is equal to
- JEE Main - 2026
- Mathematics
- Trigonometric Identities
The value of \(\dfrac{\sqrt{3}\cosec 20^\circ - \sec 20^\circ}{\cos 20^\circ \cos 40^\circ \cos 60^\circ \cos 80^\circ}\) is equal to
- JEE Main - 2026
- Mathematics
- Trigonometric Identities
- Prove the identity \( \sec^2 \theta = 1 + \tan^2 \theta \) for any right-angled triangle and use it to show that: \[ \frac{\sin \theta - \cos \theta + 1}{\sin \theta + \cos \theta - 1} = \frac{1}{\sec \theta - \tan \theta}. \]
- UK Class X - 2026
- Mathematics
- Trigonometric Identities
- If \( \sin A + \cos A = \sqrt{2} \), find the value of \( \sin A \cos A \).
- UK Class X - 2026
- Mathematics
- Trigonometric Identities
Questions Asked in JEE Main exam
If a random variable \( x \) has the probability distribution
then \( P(3<x \leq 6) \) is equal to- JEE Main - 2026
- Conditional Probability
- When 300 J of heat is given to an ideal gas with \( C_p = \frac{7}{2}R \), its temperature rises from 20°C to 50°C keeping its volume constant. The mass of the gas is (approximately) ______ g. (R = 8.314 J/mol K)
- JEE Main - 2026
- Thermodynamics
- Let \( \vec{a}, \vec{b}, \vec{c} \) be three vectors such that \[ \vec{a} \times \vec{b} = 2(\vec{a} \times \vec{c}). \] If \( |\vec{a}| = 1 \), \( |\vec{b}| = 4 \), \( |\vec{c}| = 2 \), and the angle between \( \vec{b} \) and \( \vec{c} \) is \(60^\circ\), then \( |\vec{a} \cdot \vec{c}| \) is equal to.
- JEE Main - 2026
- Vector Algebra
- A thin convex lens of focal length \( 5 \) cm and a thin concave lens of focal length \( 4 \) cm are combined together (without any gap), and this combination has magnification \( m_1 \) when an object is placed \( 10 \) cm before the convex lens.
Keeping the positions of the convex lens and the object undisturbed, a gap of \( 1 \) cm is introduced between the lenses by moving the concave lens away. This leads to a change in magnification of the total lens system to \( m_2 \).
The value of \( \dfrac{m_1}{m_2} \) is
- For the matrices \( A = \begin{bmatrix} 3 & -4 \\ 1 & -1 \end{bmatrix} \) and \( B = \begin{bmatrix} -29 & 49 \\ -13 & 18 \end{bmatrix} \), if \( (A^{15} + B) \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} 0\\ 0 \end{bmatrix} \), then among the following which one is true?}
- JEE Main - 2026
- Matrices