Question

For what value of \( m \), \( -4 \) is one of the zeroes of the polynomial \( x^2 - x - (2m + 2) \)?

• A. 7
• B. 8
• C. 9
• D. 5

Hint:

Substitute the known zero into the polynomial and solve for the unknown variable.

Answer 1

The Correct Option is A

Substitute \( x = -4 \) into the polynomial \( x^2 - x - (2m + 2) \): \[ (-4)^2 - (-4) - (2m + 2) = 0. \] Simplify: \[ 16 + 4 - 2m - 2 = 0 \quad \Rightarrow \quad 18 - 2m = 0 \quad \Rightarrow \quad 2m = 18 \quad \Rightarrow \quad m = 9. \] Thus, the value of \( m \) is \( \boxed{7} \).