Let the total production for the past \( m \) days be \( 100m \) units. After today's production of 180 units, the total production becomes \( 100m + 180 \). The average production for \( m+1 \) days is given as 110 units. Therefore, we can set up the equation for the average:
\[
\frac{100m + 180}{m+1} = 110.
\]
Multiplying both sides by \( m+1 \) to eliminate the denominator:
\[
100m + 180 = 110(m + 1).
\]
Expanding the right side:
\[
100m + 180 = 110m + 110.
\]
Now, subtract \( 100m \) and \( 110 \) from both sides:
\[
180 - 110 = 110m - 100m.
\]
Simplifying:
\[
70 = 10m.
\]
Solving for \( m \):
\[
m = \frac{70}{10} = 7.
\]
Thus, the value of \( m \) is 7.