Question:

For the non-stoichiometric reaction \(\mathrm{2A + B \rightarrow C + D}\), the following kinetic data were obtained in three separate experiments, all at 298 K.
Initial Concentration (A)Initial Concentration (B)Initial rate of formation of C (mol L-1 s-1)
0.1 M0.1 M\(1.2\times 10^{-3}\)
0.1 M0.2 M\(1.2\times 10^{-3}\)
0.2 M0.1 M\(2.4\times 10^{-3}\)
The rate law for the formation of C is :

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Compare the experiments in which only one concentration changes.
Updated On: Nov 11, 2026
  • \(\frac{dc}{dt} = k[A][B]\)
  • \(\frac{dc}{dt} = k[A]^2[B]\)
  • \(\frac{dc}{dt} = k[A][B]^2\)
  • \(\frac{dc}{dt} = k[A]\)
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The Correct Option is D

Solution and Explanation

Let rate = \(k[A]^m[B]^n\).
Experiments 1 and 2: [A] fixed, [B] doubled, rate unchanged, so \(2^n = 1\) and \(n = 0\).
Experiments 1 and 3: [B] fixed, [A] doubled, rate doubles (\(1.2\times 10^{-3} \to 2.4\times 10^{-3}\)), so \(2^m = 2\) and \(m = 1\).
Rate law: \(\frac{dc}{dt} = k[A]\).
Answer: (4) \(\frac{dc}{dt} = k[A]\)
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